If function is given y = (x – 2)²
then find out minima of this function.
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The value of the function at a maximum point is called the maximum value of the function and the value of the function at a minimum point is called the minimum value of the function.
Differentiate the given function.
let f'(x) = 0 and find critical numbers
Then find the second derivative f''(x).
Apply those critical numbers in the second derivative.
The function f (x) is maximum when f''(x) < 0
The function f (x) is minimum when f''(x) > 0
To find the maximum and minimum value we need to apply those x values in the original function.
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this is your answer
with my own rule
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