Question

if g =9.8m/s^2 on the surface of the earth , find its value at h =R/2 from the surface of the earth​

Answer 1

Answer:

Explanation:

Take the mass and radius of the Earth as MoandRo. The acceleration due to gravity as go=9.8ms−2

Now, when the mass and radius of the Earth both increase by 20%, then acceleration due to gravity would become 'g1'.

Take the new mass and radius of the Earth as 'M1'and'R1'.

But, g0=GMoR2o

and R1=120Ro100=65R0,

M1=120100M0=65M0

g1=GM1R21=G×65M0(65)×R2o=56×9.8=8.16ms−2