Question

If G be the Geometric Mean between
two numbers a and b, then the value
of
(1/(G^2-a^2))+(1/(G^2-b^2))​

Answer 1

Answer:

given G is geometric mean of a and b

G = √ab

G^2 = ab

now

1/(ab - a^2) + 1/(ab - b^2)

1/a(b-a) + 1/b(a-b)

= 1/(a-b) ((-1/a + 1/b). (b-a = -(a-b))

1/(a-b) ((a-b)/ab

= 1/ab

= 1/G^2