Physics, asked by oreyajunulgmail5073, 11 months ago

if g-cm^2-sec^-1=x Js then number x is equal to

Answers

Answered by techtro
8

The number x is equal to :

Given : g-cm^2-sec^-1=x Js

• We know that,

1 J = 1 kg m^2 / s^2

1 Js = 1 kg m^2 s / s^2

= 1 kg m^2 / s

• Also,

1 kg = 1000 g and 1 m = 100 cm

• Therefore,

1 Js = (1000 g)×(100 cm)^2 / 1 s

= 10^7 g cm^2 / s

1 g cm^2 / s = 10^-7 Js

• Hence, the value of x is 10^-7

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