If G is. Centroid of triangle ABC and O is any point then OA+Ob+OC=?
Answers
Answer:
3 OG
Step-by-step explanation:
The centroid is the centre of mass when equal masses are placed at each vertex. So G is essentially the "arithmetic mean" of the vertices. As OA, OB and OC are the position vectors of the vertices, and OG is the position vector of G, this means
OG = ( OA + OB + OC ) / 3
=> OA + OB + OC = 3 OG
Incidentally, if you put different masses at each vertex, the centre of mass is the "weighted arithmetic mean" of the vertices, and it will, of course, be a different point. For instance, if the masses at A, B, C are proportional to the opposite sides BC, CA, AB, respectively, then the centre of mass is the incentre of the triangle.
Answer:
answer Is 3OG
Step-by-step explanation:
Let O be the origin OA,OB,OC be the position vectors of triangle ABC .
Let G be the centroid of the triangle ABC and OG be the position vector of it.
we know that mean of the points A,B,C is centroid(G)
=>(OA+OB+OC)/3 = OG
=>OA+OB+OC = 3OG
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