If g is the acceleration due to gravity on the surface of the earth then the value of
acceleration due to gravity at height equal to R/2 is?
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can you repost it because question is not clear to me
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g = GM/(h^2) - equation (1) this is the formula of calculations of acceleration due to gravity where r is a distance from center of the earth
In given question
h= r+r/2=(3/2)r
put value of h in equation 1
We get
=> g1 = GM/((3/2)r)^2
=> g1 = 4GM/9r^2
=> g1 = (4/9)g ans
(sorry i could not understand your question.)
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