If G is the centroid of triangle ABC Then prove that GA bar+GB bar+GC bar=0 bar
Answers
Answered by
0
Answer:
If a triangle has vertices at
a
,
b
,
c
then GS is given by (
3
a
+
b
+
c
)
GA
=(
a
−
3
a
+
b
+
c
)
=
3
2
a
−
b
−
c
GB
=
3
2
b
−
a
−
c
,
GC
=
3
2
c
−
a
−
b
⇒
GA
+
GB
+
GC
=
3
1
(0)=0
Similar questions