Physics, asked by mangakanemp, 9 months ago

If g on the moon is one- six that on earth
1 what effect would this have on the period of pendulum of length L
2 how would the period of the pendulum differ from an equivalent one on earth

Answers

Answered by fardeenferozkhan
0

Answer:

The time period of pendulum would be 2.44 times that on earth.

Explanation:

Refer attachment for explanation!!!

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Answered by amitnrw
0

Time Period of pendulum will increase  by 2.45  (√6) times at Moon compared to Earth

Explanation:

T = 2π √(L / g)

if Length is Same

=> Tm = 2π √(L / gm)

gm = g/6

=> Tm = 2π √(L / (g/6))

=> Tm = 2π √(6L /g)

=>  Tm = √6 2π √(L / g)

=> Tm = √6 T

=>  Tm = √6 T

=> Tm = 2.45 T

Time Period will increase

Time period or pendulum of same length at Moon would be 2.45 times than Earth

if Time period is same in both cases

then 2π √(L / g)  = 2π √(Lm / gm)

=> √(L / g) = √(Lm / gm)

=> L/g  = Lm / gm

Now gm = g/6

=>  L/g  = Lm / (g/6)

=>  Lm = (L/g)(g/6)

=> Lm = L/6

To have Same Time period  Length of pendulum should be 1/6 th at moon than earth

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