Question

if g on the surface of the earth is 10m/s square inverse ,then its value at a height of 4800km will be

Answer 1

Answer:

3.25m/s^2

Explanation:

gh = g* (R^2/R+h)^2

  10 [( 6371)^2/(6371+4800)^2]

on solving gh = 3.25 m/s^2

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Answer 2

Answer:

30 m/s²

Explanation:

Given:

g (acceleration due to gravity) on the surface of the earth = 10 m/s²

We know that,

Radius of the earth = 6371 km

And,

$g \:( \: at \: a \: height \: h \: and \: radius \: r) = g_{e} {( \frac{r}{r + h} })^{2} \\ \\ g_h = 10 {( \frac{6371}{6371 + 4800}) }^{2} \\ \\ = 10 {( \frac{6371}{11171} )}^{2} \\ \\ = 10 {(1.75)}^{2} \\ \\ = 10(3) \\ \\ = 30 \: {ms}^{ - 2}$