Question

If g on the surface of the earth is 9.8 m//s^2, its value at a depth of 3200km is (Radius of the earth =6400km) is

Answer 1

Explanation:

gd=g(1-h/R)

=9.8(1-3200/6400)

=9.8(1-1/2)

=9.8×1/2

=4.9m/s^2