Question

if g=t^2/3+4t^-1/2,what is the value of g when t=64?

Answer 1

$g = (64)^{ \frac{2}{3} }+ 4 * (64 ) ^{ \frac{-1}{2} } \\ g = ( 2^{6})^{ \frac{2}{3} } + 4 * \frac{1}{8} \\ g = 2^{4} + \frac{1}{2} \\ g=16 + \frac{1}{2} \\ g = \frac{32}{2}+ \frac{1}{2} \\ g = 33/2$
             or 
16.5

Answer 2

g=t^2/3+4t^-1/2 
put t = 24
g=64(^2/3)+4*(64)^-1/2
g=(4)^3*2/3+4*(8)^2*-1/2
g=(4)^2+4*(8)^-1
g=(4)^2+4*1/8
g=16+1/2
g=32+1/2
g=33/2