Question

(If g(x) = 2x - 3 and fog(x) = 6x - 11.
then find f '(x).)
​

Answer 1

Answer:

12x²- 40x + 33 = 0

Step-by-step explanation:

2x - 3 (6x - 11) = 0

12x² - 22x - 18x + 33 = 0

12x² - 40x + 33 = 0

Answer 2

Answer:

f'(x)= x/6+11/6

Step-by-step explanation:

fog(x) = 6x-11

g(x) = 2x-3

f'(x) = ?

fog(x) = 6x-11

f(2x-3) = 6x-11

let, y = 2x-3 ==》 x = 1/2(y+3)

f(y) = 6.1/2(y+3)-11

f(y) = 6x-11

therefore, f(x) = 6x-11

Now,

let, y = 6x-11

Interchanging role of x and y

x = 6y-11

y = x/6+11/6

Therefore, f'(x) = x/6+11/6

Hence, f'(x) = x/6+11/6

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