Question

If g(x) = e2x + ex – 1 and h(x) = 3x2 – 1, the value of g(h(0)) is

Answer 1

Answer:

Step-by-step explanation:

g(h(x)) => e^2*(h(x)) + e^(h(x)) -1

h(0) = 3.0 -1 = -1

So g(h(0)) = e^2*(-1) + e^(-1) - 1

=> 1/e^2 +1/e -1