Question

If g (x) = StartFraction x + 1 Over x minus 2 EndFraction and h(x) = 4 – x, what is the value of (g circle h) (negative 3)?

Answer 1

SOLUTION

GIVEN

$\displaystyle \sf{ g(x) = \frac{x + 1}{x - 2} \: \: \: and \: \: \: h(x) = 4 - x}$

TO DETERMINE

$\displaystyle \sf{ (g \circ h)( - 3)}$

EVALUATION

Here the given functions are

$\displaystyle \sf{ g(x) = \frac{x + 1}{x - 2} }$

$\displaystyle \sf{ h(x) = 4 - x}$

Now

$\displaystyle \sf{ h( - 3) = 4 - ( - 3) = 4 + 3 = 7}$

Thus we get

$\displaystyle \sf{ (g \circ h)( - 3)}$

$\displaystyle \sf{ = g ( h( - 3))}$

$\displaystyle \sf{ = g (7)}$

$\displaystyle \sf{ = \frac{7 + 1}{7 - 2} }$

$\displaystyle \sf{ = \frac{8}{5} }$

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ If g(x)=−7x−1 and h(x)=2x+3, what is −3(g+h)(x)?

https://brainly.in/question/26186966

2. let f and g be thwe function from the set of integers to itself defined by f(X) =2x +1 and g (X)=3x+4 then the compositi...

https://brainly.in/question/22185565