Question

if g(X) x^2-3 is a factor of p(X) 2x^4+3x^3-2x^2-9x-12​

Answer 1

Answer:

Step-by-step explanation:

g(x)=x^2-3

x^2-3=3

x^2=3

x=√3

Putting x =√3 in p(x)

2(√3)^4+3(√3)^3-2(√3)^2-9(√3)-12

=2×9+3×3×√3-2×3-9×√3-12

=18+9√3-6-9√3-12

=18-6-12+9√3-9√3

=0