If general term of an AP is (3 - 4n), find its Sn.
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General term = (3-4n) ..... (i)
Putting n = 1 , in eq.(i) ,
3 - 4 × 1
= 3 - 4
= - 1
Therefore, the first term(a) is -1 .
Putting n = 2 in eq. (i) ,
3 - 4 × 2
= 3 - 8
= - 5
Therefore, the second term is -5.
Common difference(d) = second term - first term
= -5 - (-1)
= -5 + 1
= - 4
Sn = n/2 ( 2a + (n-1) d)
= n/2 ( 2 × -1 + (n-1) -4)
= n/2 ( -2 - 4n + 4 )
= n/2 ( 2- 4n )
= n - 2n^2
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