Question

If given concentrations of BAP are 0.5 UM,
5 uM, 50 uM then find out the amounts
(in PPM) of BAP for shoot modification for respective
concentrations (M. wt of BAP-225)
(1) 0.5, 5.0,50
(2) 0.1, 1.0, 11
(3) 10, 100, 1000 (4) 50, 500, 5000
Motob the
11​

Answer 1

Answer:

the first experiment, the table of variance analysis indicated that different media (MS and QL) and various concentrations of BAP and BA had a significant effect on proliferation rate, height and callus weight. With respect to quality index, differ- ent media supplemented with various concentrations of BAP and not BA had significant effect on quality (Table 1). The highest number of new micro-shoot was obtained in MS med- ium containing 1 mg l À1 , in which the average number of new micro-shoot was 8.5 (Table

Answer 2

The correct ans is 2) 0.1, 1.0, 11 .

Explanation:.

The concentration of BAP in solution (micromoles/dL) microM are 0.5 uM,  

5 uM, 50 uM .

M. wt of BAP is 225

The formula of PPM is  (uM × Molecular weight) ÷ 1000

1)  When the concentration of BAP is 0.5 uM.

M. wt of BAP is 225

∴Concentration ppm (parts-per-million) is 0.11 ppm

2)  When the concentration of BAP is 5 uM.

M. wt of BAP is 225  

∴Concentration ppm (parts-per-million) is 1.12500 ppm

3)  When the concentration of BAP is 50 uM.

M. wt of BAP is 225  

∴Concentration ppm (parts-per-million) is 11.25000 ppm

SO the correct answer is 2) 0.1, 1.0, 11