Biology, asked by ankitmohanty100, 11 months ago

If given concentrations of BAP are 0.5 uM,
5 uM, 50 uM then find out the amounts
(in PPM) of BAP for shoot modification for respective
concentrations (M. wt of BAP-225)
(1) 0.5, 5.0,50 (2) 0.1, 1.0, 11
(3) 10, 100, 1000 (4) 50, 500, 5000​

Answers

Answered by anuraghmoni35
0

Answer:

Explanation:

I'm having problems with the multiplication of shoots from nodal explant of Tetrastigma. I use a synthetic cytokinin (BAP) and auxin (NAA) in the range of 1-5mg/L (for BAP) and 0.1 - 0.2mg/L (for NAA). The result doesn't give a high multiplication rate of the shoots. I am also getting a high level of contamination of explant that I am transferring to the initiation media using coconut water as a source of hormone. I am using murashige-skoog (MS) as a basal medium. Can anyone give me some advice?

Answered by mintu78945
10

If given concentrations of BAP are 0.5 uM,

5 uM, 50 uM then in PPM it is 0.1, 1.0, 11 .

Explanation:

The concentration of BAP in solution (micromoles/dL) microM are 0.5 uM,

5 uM, 50 uM .

M. wt of BAP is 225

1)

  • When the concentration of BAP is 0.5 uM.
  • M. wt of BAP is 225
  • Concentration g/L  is 0.000112 g/L
  • Concentration milligrams/L  is 0.11200 milligrams/L
  • Concentration ppm (parts-per-million)  is 0.11200 ppm

2)

  • When the concentration of BAP is 5 uM.
  • M. wt of BAP is 225
  • Concentration g/L  is 0.001125 g/L
  • Concentration milligrams/L  is 1.12500 milligrams/L
  • Concentration ppm (parts-per-million)  is 1.12500 ppm

3)

  • When the concentration of BAP is 5o uM.
  • M. wt of BAP is 225
  • Concentration g/L  is 0.011250 g/L
  • Concentration milligrams/L  is 11.25000 milligrams/L
  • Concentration ppm (parts-per-million)  is 11.25000 ppm

So the correct answer is 2) 0.1, 1.0, 11

Similar questions