If given that clock in 35 minutes fast, then the correct time before half an hour in the morning will be
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Answered by
1
Answer:
The answer is option D
Speed of 1
st
clock =58min/hr
Speed of 2
nd
clock =61min/hr [Since it gains 2min in 2hrs, it should gain 1min in 1hr]
Relative velocity of 2
nd
clock wrt 1
st
=61−58=3min/hr
Relative distance travelled by the 2
nd
clock wrt 1
st
by the time both are stopped =1hr6min=66min
Time taken by the 2
nd
clock wrt 1
st
to cover 66min=66/3=22hours
In those 22 hours, mins covered by the 1
st
clock =22×58=1276
The actual mins elapsed in those 22hours=22×60=1320
∴ Number of mins the 1
st
clcok is behind the correct time=1320−1276=44mins
⇒ If the time on the 1
st
clock is 9am, then the correct time is 9:44am
Answered by
5
Answer:
The answer is option D
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