if given that the first term of the geometric progression is 5 and the sixth term is 1215.Find the 10th term?
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→ T1 = a = 5
T6 = ar⁵ = 1215 a = 1215/r⁵
5 = 1215/r⁵
r⁵ = 1215/5 =243
→ r = 3
→ T10 = ar9 = 5(3)⁹ = 98415
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