Question

if goods are purchased for rs.840 and one-fourth be sold at a loss of 20% at what gain percent should the remainder be sold so as to gain 20% on the whole transaction?

Answer 1

$<u><b>Hi !<b><u>$

Here is your answer !!

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C.P. of goods = ₹ 840

Profit % = 20 %

S.P. of goods = ?

$s.p. \: = \: \frac{(100 \: + profit \: \%)}{100} \: \times c.p. \\ \\ = > \frac{100 + 20}{100} \times \: 840 \\ \\ = > \frac{120}{100} \: \times 840 \\ \\ = > 1008$

S.P. of goods = ₹ 1008

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C.P. of 1/4 of goods = 1/4 × 840

=> ₹ 210

Loss % = 20 %

S.P. of 1/4 of good = ?

$s.p. \: = \frac{100 - 20 \: }{100} \: \times 210 \\ \\ = > \frac{80}{100} \times 210 \\ \\ = > 168$

S.P. of 1/4 of goods = ₹ 168

Remaining goods = 1 - 1/4 = 3/4 of goods

S.P. of remaining goods = 3/4 × 1008

=> ₹ 756

C.P. of remaining goods = 3/4 × 840

=> ₹ 630

Gain = ₹ 756 - ₹ 630 = ₹ 126

Gain % = ?

$gain \: \% \: = \: \frac{total \: gain}{c.p.} \: \times 100 \\ \\ = > \frac{126}{630} \times 100 \\ \\ = > 20 \: \%$

Ans ) The remainder should be sold at a gain of 20 %

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Thanks !!

Answer 2

Answer:

20 °/.

Step-by-step explanation:

C.P. of 1/4 of goods = 1/4 × 840

=> ₹ 210

Loss % = 20 %

S.P. of 1/4 of good = ?

\begin{gathered}s.p. \: = \frac{100 - 20 \: }{100} \: \times 210 \\ \\ = > \frac{80}{100} \times 210 \\ \\ = > 168\end{gathered}s.p.=100100−20×210=>10080×210=>168

S.P. of 1/4 of goods = ₹ 168

Remaining goods = 1 - 1/4 = 3/4 of goods

S.P. of remaining goods = 3/4 × 1008

=> ₹ 756

C.P. of remaining goods = 3/4 × 840

=> ₹ 630

Gain = ₹ 756 - ₹ 630 = ₹ 126

Gain % = ?

\begin{gathered}gain \: \% \: = \: \frac{total \: gain}{c.p.} \: \times 100 \\ \\ = > \frac{126}{630} \times 100 \\ \\ = > 20 \: \%\end{gathered}gain%=c.p.totalgain×100=>630126×100=>20%

Ans ) The remainder should be sold at a gain of 20 %