Question

if GP= 1, 2r, 3r^2, 4r^3.... what is sum of all the terms

Answer 1

Answer:

Tis is A. G. P

S=a/(1-r)+dr/(1-r)^2 where d=1, a=1,r=r

=1/(1-r) +r/(1-r)^2 =(1-r+r)/(1-r)^2 =1/(1-r) ^2

Answer 2

Answer:

Tis is A. G. P

S=a/(1-r)+dr/(1-r)^2 where d=1, a=1,r=r

=1/(1-r) +r/(1-r)^2 =(1-r+r)/(1-r)^2 =1/(1-r) ^2

Step-by-step explanation: