if gravitational constant (G), planck's constant (h) and velocity of light (c) are fundamental quantities, the dimension of radius of gyration will be
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Answer:
Dimension of the Gravitational constant
G
=
[
M
]
−
1
[
L
]
3
[
T
]
−
2
Dimension of Planck's constant
h
=
[
M
]
[
L
]
2
[
T
]
−
1
Dimension of the velocity of light
c
=
[
L
]
[
T
]
−
1
Radius of Gyration will have units of length. Let the dimension of length in new system be
[
L
]
=
[
G
]
x
[
h
]
y
[
c
]
z
Using first three dimensions we get
[
L
]
=
(
[
M
]
−
1
[
L
]
3
[
T
]
−
2
)
x
(
[
M
]
[
L
]
2
[
T
]
−
1
)
y
(
[
L
]
[
T
]
−
1
)
z
⇒
[
M
]
0
[
L
]
1
[
T
]
0
=
[
M
]
−
x
+
y
[
L
]
3
x
+
2
y
+
z
[
T
]
−
2
x
−
y
−
z
Comparing power of respective items on both sides we get
−
x
+
y
=
0
......(1)
3
x
+
2
y
+
z
=
1
......(2)
−
2
x
−
y
−
z
=
0
.....(3)
Adding (2) and (3) we get
x
+
y
=
1
.....(4)
Adding (1) and (4)
2
y
=
1
⇒
y
=
1
2
........(5)
Inserting this value in (4)
x
+
1
2
=
1
⇒
x
=
1
2
.......(6)
Inserting value of
x
and
y
in (2)
3
×
1
2
+
2
×
1
2
+
z
=
1
⇒
z
=
−
3
2
......(7)
Dimension becomes
[
L
]
=
[
G
]
1
2
[
h
]
1
2
[
c
]
−
3
2
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