Science, asked by anshudp0605, 1 year ago

If gravitational force between two body is F . If distance between them is increased by a factor of 1/3 .Then find the new gravitational force between them ?​


omkar20011: new gravational is 9f
Anonymous: 9/4 F
Anonymous: 9/16 F
Anonymous: lower is right
Anonymous: if r is increased by 1/3 then r'=4/3r
Anonymous: then with formula F'=4/9F
mohdazeem88ma: F`=9/16 F
aman200547: thats what i m saying

Answers

Answered by Anonymous
158

⭐《ANSWER》

\huge\mathfrak{\underline {\underline\pink {ANSWER}}}

↪Actually welcome to the concept of the GRAVITATION

↪Basically here we are going to use the NEWTON'S LAW OF GRAVITATION ,

since we , know that ,

〽F = GMm/R^2

↪Initially here , the Separation is Only R , now as here given , the separation is changed to 1/3 times of original, so end up getting as

↪New Separation as R/3 , now the New acting force will be as ,

F' = GMm/(R/3)^2

F' = GMm / R^2÷9

F' = 9GMm/R^2

so we get as ,

〽F' = 9F

↪⭐so the New Gravitational Force is 9F


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Answered by MadamCurie
90

\mathfrak{\underline{\underline{answer :-}}}}}

Given :-

Initial Gravitational force is " F"

Initial length :- R

If length is increased by 1/3 then final length would be

R × 1/3 = R/3

Final gravitational force = ??

As,we know that

F = GMm/r^2

F(i)= GMm/R^2 ----------(1)

(1) is initial gravitational force

Substute R = R/3

F = GMm/(R/3)^2

F = GMm/R^2/9

F = 9GMm/R^2

On sending the denominator to numerator , the fr action gets reversed.

From equation (1)

F = 9F(i)

So gravitaiona force is increased 9 times to that of initial when "r" is increased to 1/3 times.

====================

note :-

Initial and final are the words which are taken for better understanding

=========

additional info :-

GRAVITATIONAL FORCE :- it is a force which attracts everything ,which has mass towards it .

The above used formula is newton's universal law of gravitation.

=============


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