If gravitational force between two objects were proportional to 1/r,where r is separation beteeen them ,then a partucle in circular orbit under such a force would have its orbital speed v proportional to
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Answered by
40
F ∝ 1/R
or,
F =kR
Now, when one of the particles goes around the other then it is acted upon by a centripetal force given by:
Fcentri = mv^2/R
now,
mv^2/R = kR
v = R√(k/m)
or
v ∝ R
ANSWER : R
or,
F =kR
Now, when one of the particles goes around the other then it is acted upon by a centripetal force given by:
Fcentri = mv^2/R
now,
mv^2/R = kR
v = R√(k/m)
or
v ∝ R
ANSWER : R
Answered by
31
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