if h-50=h/√3 , then prove: h=75+25√3
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h-50 = h/√3
√3 h -50√3= h
h(√3-1) = 50√3
h=50√3/(√3-1)
Not rationalising
h= 50√3 *(√3+1)/(3-1)
h= (150 +50√3)/2
h= 75+25√3
√3 h -50√3= h
h(√3-1) = 50√3
h=50√3/(√3-1)
Not rationalising
h= 50√3 *(√3+1)/(3-1)
h= (150 +50√3)/2
h= 75+25√3
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