Question

if H.C.F of (210,55) is the expressible in the form 210*55x. Find the value of x.​

Answer 1

Answer:

210 = 55 * 3 + 45

55 = 45 * 1 + 10

45 = 10 * 4 + 5

10 = 5 * 2

hence 5 is the HCF.

5 = 45 - 10 * 4 substitute the values of 10 and 45 from above equations.

= 210 - 55 * 3 - (55 - 45 ) 4

= 210 - 55 * 3 - 55 * 4 + 45 * 4

= 210 - 55 * 7 + (210 - 55 * 3) * 4

= 210 * 5 - 55 * 19

so x = 5 and y = -19

Step-by-step explanation:

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Answer 2

Answer:

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