If H.C.F of two numbers is 28 and L.C.M is 17.If one the number is 6,find other number
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Answered by
3
Given:
HCF= 28
LCM= 17
One number= 6
then,then the other number is
let other number be. x
We know that
HCF× LCM= Product of two numbers
28*17= 6*x
then, x= 28*17/6
=79.3
= 79(approx.)
Hope it helps you ❣️☑️☑️
Answered by
0
⭐⭐
According to theorem
HCF(A,B)×LCM(A,B) = A×B
Let other number be a
Now HCF(a,6) and LCM(a,6) are given
Put these in the equation
28×17=6×a
a=28×17/6
a=79.333333.....
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