Question

If H,C,V are the height C S A and volume of cone . Prove that 3πvh³-c²h²+9v²=0.

Answer 1

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Answer 2

C = πrl
V = 1/3 πr²h
r² = 3V/πh
now,
c = πr√(h²+r²)
c² = π²r²(h²+r²)
c² = π²×3V/πh×(h²+3V/πh)
c²h² = 3πVh³+9V²
3πVh³ - c²h² + 9V² =0
Hence proved