If h, Cand V respectively are the height, the curved surface area and volume of the cone. Prove that 3πVh3-C2h2+9V2=0.
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The curved surface area of a cone =C=πrl=πr√(h²+r²)where h, l and r are the height, slant height and radius of the cone.Volume of the cone=V=πr²h/3∴3πVh³-C²h²+9V²=3π{(πr²h)/3}h³-{πr√(h²+r²)}²h²+9(πr²h/3)²=π²r²h⁴-π²r²(h²+r²)h²+9π²r⁴h²/9=π²r²h⁴-π²r²h⁴-π²r⁴h²+π²r⁴h²=0 (Proved)source:-https://brainly.in/question/1025307#readmore
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