Question

If H+ ions concentration is 10-4 , what would be the concentration of OH- ions​

Answer 1

H+ + OH- = 14

Explanation:

H+ =4

OH- = 14-4

=10

Answer 2

Answer:

$\boxed{\mathfrak{[OH^-] = {10}^{ - 10}}}$

Explanation:

The ion product constant for water ($\rm K_w$) is the equilibrium constant ($\rm K_{eq}$) expression for the self-ionization of water i.e.

$\boxed{ \bold{K_{eq} = K_w = [H^+] [OH^-] = 1.0 \times 10^{-14}}}$

According to the question:

$\rm [H^+] = 10^{-4}$

So,

$\rm \implies [OH^-] = \dfrac{10^{-14}}{[H^ + ]} \\ \\ \rm \implies [OH^-] = \dfrac{10^{-14}}{ {10}^{ - 4} } \\ \\ \rm \implies [OH^-] = {10}^{ - 14 - ( - 4)} \\ \\ \rm \implies [OH^-] = {10}^{ - 14 + 4} \\ \\ \rm \implies [OH^-] = {10}^{ - 10}$