if H is a subgroup of G then HH=H
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Step-by-step explanation:
H H=H
We will show that HH ⊆ H
Then x ∈ H H
Then x = ab where a ∈ H and b ∈ H
H H = H and H − 1 =H
I already mentioned that HH=H.
We know that H < G.
We have
H−1={h−1:h∈H}.
Let x ∈ H − 1.
Then x = h − 1 for some h ∈ H. Because H < G, we have h − 1 ∈ H. Thus, x ∈ H.
Hence, H−1⊂H.
Let y ∈ H.
Then y − 1 ∈ H. Hence, y = ( y − 1 ) − 1 ∈ H − 1 . Thus, H ⊂ H − 1
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