Question

If h is orthocenter of triangle ABC then (sin angle bhc) =

Answer 1

Presently consider the digression lines at F for the two circles.

At that point, let G be a point both on the digression line for the hover on AH and on BC.

Additionally, let I be a point both on the digression line for the hover on BC and on AC.

Presently we have ∠CFG=∠FAH, ∠IFC=∠FBC Since ∠FAH+∠FBC=∠BAD+∠ABD=90∘ we have ∠CFG+∠IFC=90∘.