Question

if h is planck's constant the momentum of a photon of wavelength 0.01 angestron is​

Answer 1

Explanation:

use de-broglie wavelength formula

Answer 2

The momentum of a photon is $6.63\times 10^{-22}\ kg-m/s$.

Explanation:

Given that,

Wavelength of the photon, $\lambda=0.01\ A=0.01\times 10^{-10}\ m$

We need to find the momentum of a photon. It is a concept of De- Broglie wavelength. It is given by :

$\lambda=\dfrac{h}{p}$

h is the Planck's constant

p is the momentum

$p=\dfrac{h}{\lambda}$

$p=\dfrac{6.63\times 10^{-34}}{0.01\times 10^{-10}}$

$p=6.63\times 10^{-22}\ kg-m/s$

So, the momentum of a photon is $6.63\times 10^{-22}\ kg-m/s$. Hence, this is the required solution.

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De- Broglie wavelength

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