if h is the depth of orifice below free surface of liquid in velocity of class is directly proportional to
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Explanation:
From Equation of continuity we have
A V = a v , where 'A' is the area of free surface and 'a' is the area of the orifice ,,,,,,,,,,,,,,,,,,,,,,(1}
Applying Bernoulli`s principle
p1 + ρgh1 + 21ρV2 = p2 + ρgh2 + 21ρv2
p + ρgh + 21ρV2 = p + 0 + 21ρv2 , as h2 = 0 as point 2 is taken as reference point
gh = 21 ( v2−V2 ) ........................(2)
from 1st eqn we have V = av /A , now put this in 2nd we get
v2(1−(A2a2)) = 2gh
hence , v2 = 1−(A2a2)2gh = 2gh ( A2−a2A2)
hence option (C) is correct
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