Question

if h is the height rise of liquid in long capillary of tube of radius r,then which of the following relation will be correct for a given liquid?? 1. hr^2=constant 2. h/r^2 3.h/r= constant 4. hr = constant​

Answer 1

Answer:

option D) hr=constant

Answer 2

Given:

h is the height rise of liquid in long capillary of tube of radius r.

To find:

• hr² = constant
• h/r² = constant
• h/r = constant
• hr = constant

Calculation:

The expression for rise of liquid in a capillary tube is given as :

$\boxed{ \bf \: h = \dfrac{2T \cos( \theta) }{ \rho \times r \times g} }$

• T is the surface tension
• $\theta$ is the angle of contact between the fluid and the surface.
• $\rho$ is the density of the fluid.
• g is the gravitational acceleration.

Now, for a single liquid , values of $\rho$ and T will become constant :

$\sf \implies \: h = \dfrac{constant}{r}$

$\sf \implies \: hr = constant$

So, final answer is:

$\boxed{ \bf \: hr = constant}$