Physics, asked by Ritikjoshi21q, 3 months ago

If h is the height rise of liquid in long capillary tube of radius r, then which of the following relation will be correct for a given liquid?

hr2 = constant

h/r2 = constant

h/r = constant

hr = constant​

Answers

Answered by intekhazm
3

Answer:

option:D) hr=constant

Attachments:
Answered by dualadmire
2

Given:

Height of the liquid in the capillary tube = h

Radius of the capillary tube = r

To find:

The correct options.

Solution:

We know that the height at which the liquid rises in a capillary tube is given by:

h = 2T cosθ/ rρg

Here T is the surface tension of the liquid,

θ is the angle of contact,

r is the radius of the capillary tube,

ρ is the density of water,

And g is acceleration due to gravity.

When T, cosθ, ρ and g are constant then:

h ∝ 1/r

hr = constant

Option D is correct.

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