If h:k = 2:5, x:y = 3:4 and 2h+x:k+2y = 1:2, find the ratio h-x : k-y
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Given info : If h : k = 2 : 5, x : y = 3 : 4 and 2h+x : k+2y = 1 : 2
To find : The ratio of (h - x) : (k - y) is ...
solution : a/c to question,
h/k = 2/5
so h = 2r and k = 5r (where r is proportional constant)
and x/y = 3/4
so x = 3s and y = 4s (where s is proportional constant)
now, (2h + x)/(k + 2y) = 1/2
⇒(2 × 2r + 3s)/(5r + 2 × 4s) = 1/2
⇒(4r + 3s)/(5r + 8s) = 1/2
⇒8r + 6s = 5r + 8s
⇒3r = 2s ....(1)
now, (h - x)/(k - y)
= (2r - 3s)/(5r - 4s)
= (2r - 3 × 3r/2)/(5r - 2 × 3r) [ from eq (1). ]
= (2r - 9r/2)/(5r - 6r)
= (4r - 9r)/2(-r)
= -5r/-2r
= 5/2
therefore the ratio (h - x) : (k - y) = 5 : 2
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