if h,k are two perpendicular distance from (1,2,3) to the x axis, z axis respectively then hk =
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Answer:
The perpendicular distance of the point (1,2,3) from x axis will be
h=
(y
2
+z
2
)
=
(2)
2
+(3)
2
=
4+9
=
13
The perpendicular distance of the point (1,2,3) from z axis will be
k=
(x
2
+y
2
)
=
(1)
2
+(2)
2
=
1+4
=
5
⇒ hk=
13
.
5
=
65
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