If h+. + oh- = h2o +13.7 kcal then heat of complete neutralisation of one gram mole of h2so4 with strong base will be
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Answered by
19
27.4 kcal is answer !
13.7 kcal is already there in the reaction and we known reaction b/w strong acid and strong base gives 13.7 kcal so, adding both
We get ,
13.7+13.7=27.4 kcal
Answered by
3
Given:
The equation - h+. + oh- = h2o +13.7
To Find:
Heat of complete neutralisation of one gram mole of h2so4
Solution:
The reaction of two protons with twp hydroxide ions is equivalent to the complete neutralisation of one gramme mole of H 2 SO 4 with the strong base.
If h+. + oh- = h2o +13.7 then the heat of complete neutralisation of one gram mole of H2so4 with the strong base will be 27.4Kcal -
H2so4 ⇆ 2H+ + So2/4
2H+ + 2OH ⇆ 2H2O + 27.4
13.7 × 2
= 27.4
Answer: Heat of complete neutralisation of one gram mole of h2so4 is 27.4 Kcal
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