Question

If h(x)=2x³+(6a²-10)x²+(6a+2)x-14a-2 is exactly divisible by x-1 but not by x+1, find the value of a

Answer 1

Answer:

$a = \frac{2}{3}$

a=-2

Step-by-step explanation:

X=1

$2 + 6a {}^{2} - 10 + 6a + 2 - 14a - 2$

a=-2

a=2/3

Answer 2

Step-by-step explanation:

Answer:

a = \frac{2}{3}a=

3

2

a=-2

Step-by-step explanation:

X=1

2 + 6a {}^{2} - 10 + 6a + 2 - 14a - 22+6a

2

−10+6a+2−14a−2

a=-2

a=2/3