Question

if h(x) =x/x2-9 and g(x) =6x find the values of x for which hg(x) is meaningless

Answer 1

2x/(12x²-3)

Explanation:

Given,

h(x) = x/(x²-9) and g(x)=6x

Now,

h(g(x)) = h(6x)

= 6x/{(6x)²-9} = 6x/(36x²-9)

= 2x/(12x²-3)