If h(x) = x2–2x, k(x) = 2x + 3 and hok'(x) = 3, then find the value of'x'
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Answer:
ok
Step-by-step explanation:
(fog)(x)=f(g(x))=2(3x+2)−1=6x+4−1=6x+3=3(2x+1)
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