if h (x) =x²-kx+4 and h(1)=7 then find the value of k,find the value of x
Answers
Answered by
1
Answer:
Step-by-step explanation:
At x=2,f(2)=k(2)+5=2k+5
x→2
+
lim
f(x)=
h→0
lim
f(2+h)
=
h→0
lim
[(2+h)−1]=
h→0
lim
(1+h)=1
x→2
−
lim
f(x)=
h→0
lim
f(2−h)=
h→0
lim
[k(2−h)+5]
=
h→0
lim
[(2k+5)−kh]=2k+5
Now,
x→2
lim
f(x) exists only when 2k+5=1⟹k=−2.
When k=−2, we have
x→2
lim
f(x)=f(2)=1
Hence, f(x) is continuous at x=2, when k=−2.
Answered by
0
Answer:
the value of k is 2.
x ki value ni pta
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