Question

if h1=3 cm and h2 = 1 cm and acceleration of beaker in horizontal direction is
2 m/s, then the separation between the points A and B is​

Answer 1

Answer:

Separation between A and B is 10 cm

Explanation:

As we know that liquid remains in equilibrium with respect to the container

so here with respect to the container the condition of equilibrium of liquid is given as

$Ncos\theta = mg$

$N sin\theta = ma$

so we have

$\frac{a}{g} = tan\theta$

$a = g tan\theta$

now we also have

$tan\theta = \frac{h_3 - h_2}{L}$

so we have

$a = g \frac{h_3 - h_2}{L}$

so we have

$2 = 10 \frac{3 cm - 1 cm}{L}$

$L = 10 cm$

So the separation between A and B is L = 10 cm

#Learn

Topic : Fluid Statics

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