If h2s gas is not available then which gas should we choose for detection of group 2 in basic radical
Answers
Answered by
0
Why do we pass H2S in presence of HCL during salt analysis of Group 2 basic radicals?
The whole idea about the cation separation procedure is to separate the cations (heavy metals) by their different solubility of their sulfides.
If you add H2S in the presence of HCl the sulfide concentration will be very low so only the sulfides of: Mercury (black), Lead(black), Bismuth (black-brown), Copper (black), Cadmium (yellow), Tinn (yellow), Arsenic(yellow) and Antimony (brown-orange) will fall out.
If you did not add HCl, you would get the sulfides of Iron, Cobalt, Nickel, Zink and Manganese, too!
Funny...... Ok it isn't.
Mark mr brainiest
Similar questions