If haemoglobin contains 4 atoms of iron, then approximate molecular mass
of haemoglobin is (at. mass of Fe = 55.85)
Answers
Explanation:
Let molecular mass of heamoglobin molecule be
=
M
One molecule of heamoglobin contains
4
Fe
atoms of atomic mass
=
55.85
each
,
Total mass of iron in one molecule of heamoglobin
=
4
×
55.85
=
223.4
To calculate the percentage of iron:
M
amu of heamoglobin has iron
=
223.4
100
amu of heamoglobin has iron
=
223.4
M
×
100
Equating to the given value,
223.4
M
×
100
=
0.335
Solving for
M
,
M
=
223.4
0.335
×
100
=
66686.57
g
m
o
l
−
1
, rounded to two decimal places.
.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.
At some places the iron percentage in heomoglobin is given as
0.3335
%
. Using the published average atomic mass of iron as
55.847
,
M
=
66982.9085
g
m
o
l
−
1
Answer:
Let molecular mass of heamoglobin molecule be
=
M
One molecule of heamoglobin contains
4
Fe
atoms of atomic mass
=
55.85
each
,
Total mass of iron in one molecule of heamoglobin
=
4
×
55.85
=
223.4
To calculate the percentage of iron:
M
amu of heamoglobin has iron
=
223.4
100
amu of heamoglobin has iron
=
223.4
M
×
100
Equating to the given value,
223.4
M
×
100
=
0.335
Solving for
M
,
M
=
223.4
0.335
×
100
=
66686.57
g
m
o
l
−
1
, rounded to two decimal places.
.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.
At some places the iron percentage in heomoglobin is given as
0.3335
%
. Using the published average atomic mass of iron as
55.847
,
M
=
66982.9085
g
m
o
l
−
1