if half of chappati is distributed among three puppies what fraction of each chappati each puppy got
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1/3 is the fraction of food puppies ate
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Lets say their mom made x chapatis
Solution :
number of chapatis left after first son: 2(x-1)/3
number of chapatis left after second son: 2(2(x-1)/3 – 1)/3 = (4(x-1) – 6)/9 = (4x -10)/9
number of chapatis left after third son: 2((4x -10)/9 -1)/3 = (8x – 20 – 18)/27 = (8x – 38)/27
they ate ((8x-38)/27 -1)/3 chapatis each in the night
So it should be an integer value, lets say it is y, where y is an integer.
(8x-38 – 27)/81 = (8x – 65)/81 = y
x = (81*y+ 65)/8 = 10y + (65+y)/8 = 10y + 8 + (y+1)/8
as x should also be an integer
y can be => 7, 15, 23, ….
x can be = 79, 160, 241
minimum value of x is 79.
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