Question

If have a pure Na2SO4 sample that contains a total of 7 billion electrons, then find the number of moles of Na2SO4present in the sample.​

Answer 1

Answer:

answer in attachment

Answer 2

Answer:

The number of moles of Na₂SO₄ present in the sample is equal to 10⁸ moles.

Explanation:

Given, the total electrons present pure Na₂SO₄ sample = 7×10⁹

We know that the atomic number of sodium, Sulphur and oxygen are 11, 16 and 8 respectively.

The number of electrons in 1 mole of  Na₂SO₄:-

= 2  (11) + 16 + 4 (8)

= 22 + 16 + 32

= 70 electrons

Therefore, one mole of Na₂SO₄ contains  electrons = 70

The amount of Na₂SO₄ contains 70 electrons =  1 mole

The amount of Na₂SO₄ contains  7 billion or 7×10⁹ electons:-

Moles of Na₂SO₄ =  $\frac{7\times 10^9}{70}= 10^8 \; moles$

Therefore, the number of moles of Na₂SO₄ present in the sample is equal to 10⁸ moles.

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