If HCF [12,15] =3,find LCM [12,15]
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LCM = 60
We have,
LCM = Product of two given numbers / their HCF
LCM(12,15) = (12 × 15) / HCF(12,15)
LCM(12,15) = 180/3
LCM(12,15) = 60
•°• The required number or the LCM(12,15) is 60.
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Using prime factorisation method:
(i) 12, 15 and 21
Factor of 12=2×2×3
Factor of 15=3×5
Factor of 21=3×7
HCF (12,15,21)=3
LCM (12,15,21)=2×2×3×5×7=420
(ii) 17, 23 and 29
Factor of 17=1×17
Factor of 23=1×23
Factor of 29=1×29
HCF (17,23,29)=1
LCM (17,23,29)=1×17×23×29=11,339
(iii) 8, 9 and 25
Factor of 8=2×2×2×1
Factor of 9=3×3×1
Factor of 25=5×5×1
HCF (8,9,25)=1
LCM (8,9,25)=2×2×2×3×3×5×5=1,800
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